Sanibel Island, Florida, USA
Latitude and longitude coordinates are: 26.443398, -82.111511.
Sanibel Island is a wonderful natural island located near the western shores of Florida, near Cape Coral city. There is the same name town in the island, with about 5,000 people living there. Sanibel island is a desired destination for those tourists who enjoy exploring small islands like that, enjoy local nature and old historic monuments like a small lighthouse, etc.
Where is Sanibel Island, Florida, USA on Map?
Road map of Sanibel Island, Florida, USA shows where the location is placed.
Satellite Map of Sanibel Island, Florida, USA
Sanibel Island, Florida, USA Lat Long Coordinates Info
The latitude of Sanibel Island, Florida, USA is 26.443398, and the longitude is -82.111511. Sanibel Island, Florida, USA is located at United States country in the Islands place category with the gps coordinates of 26° 26' 36.2328'' N and 82° 6' 41.4396'' W.
Country | United States |
---|---|
Latitude | 26.443398 |
Longitude | -82.111511 |
DMS Lat | 26° 26' 36.2328'' N |
DMS Long | 82° 6' 41.4396'' W |
UTM Easting | 389,179.25 |
UTM Northing | 2,925,267.60 |
Category | Islands |
Country Code | US |
Zoom Level | 10 |
Coordinates of Sanibel Island, Florida, USA is given above in both decimal degrees and DMS (degrees, minutes and seconds) format. The country code given is in the ISO2 format.
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